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K. Ramesh ^{1}, M. Thirumalaiswamy ^{2} and S.Kavunthi ^{3}

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In this paper, a new class of sets called intuitionistic fuzzy wgrαclosed sets is introduced and their properties are studied. Moreover the notions of applications of an intuitionistic fuzzy wgrαclosed sets, intuitionistic fuzzy wgrαcontinuity and intuitionistic fuzzy wgrαirresoluteness are introduced
Keywords 
Intuitionistic fuzzy topology, intuitionistic fuzzy wgrαclosed sets, IFwgrT1\2 space, IFwgrαT1\2 space and intuitionistic fuzzy wgrαcontinuity. 
2010 Mathematics Subject Classification: 54A40, 03F55. 
INTRODUCTION 
In 1965, Zadeh[12] introduced fuzzy sets and in 1968, Chang[2] introduced fuzzy topology. After the introduction of fuzzy sets and fuzzy topology, several researches were conducted on the generalizations of the notions of fuzzy sets and fuzzy topology. The concept of intuitionistic fuzzy sets was introduced by Atanassov[1] as a generalization of fuzzy sets. In 1997, Coker [3] introduced the concept of intuitionistic fuzzy topological spaces. In this paper, we introduce the concepts of intuitionistic fuzzy wgrαclosed sets, intuitionistic fuzzy wgrαopen sets and intuitionistic fuzzy wgrαcontinuity and study some of their properties in intuitionistic fuzzy topological spaces. 
PRELIMINARIES 
Throughout this paper, (X, τ) or X denotes the intuitionistic fuzzy topological spaces (briefly IFTS). For a subset A of X, the closure, the interior and the complement of A are denoted by cl(A), int(A) and Ac respectively. We recall some basic definitions that are used in the sequel. Definition 2.1: [1] Let X be a nonempty fixed set. An intuitionistic fuzzy set (IFS for short) A in X is an object having the form A = {⟨x, μA(x), νA(x)⟩/ x ∈ X} where the functions μA : X → [0,1] and νA : X → [0,1] denote the degree of membership (namely μA(x)) and the degree of nonmembership (namely νA(x)) of each element x∈ X to the set A, respectively, and 0 ≤ μA(x) + νA(x) ≤ 1 for each x ∈ X. Denote by IFS(X), the set of all intuitionistic fuzzy sets in X. 
Definition 2.2: [1] Let A and B be IFSs of the form A = {⟨x, μA(x), νA(x)⟩/ x ∈ X} and B = {⟨x, μB(x), νB(x)⟩/ x∈ X}. Then 
(i) A ⊆ B if and only if μA(x) ≤ μB(x) and νA(x) ≥ νB(x) for all x ∈ X, 
(ii) A = B if and only if A ⊆ B and B ⊆ A, 
Definition 2.9: An IFS A = {⟨ x, μA(x), νA(x) ⟩ / x ε X} in an IFTS (X, τ) is called an 
(i) intuitionistic fuzzy generalized closed set (IFGCS for short) if cl(A) ⊆ U whenever A ⊆ U and U is an IFOS[11] 
(ii) intuitionistic fuzzy α generalized closed set (IFαGCS for short) if αcl(A) ⊆ U whenever A⊆ U and U is an IFOS in X.[9] 
(iii) intuitionistic fuzzy generalized semi closed set (IFGSCS for short) if scl(A) ⊆ U whenever A ⊆ U and U is an IFOS [10] 
(iv) intuitionistic fuzzy regular generalized αclosed set (IFRGαCS for short) if αcl(A) ⊆ U whenever A ⊆ U and U is an IFRαOS in X.[6] 
An IFS A is said to be an intuitionistic fuzzy generalized open set (IFGOS for short), intuitionistic fuzzy αgeneralized open set (IFαGOS for short), intuitionistic fuzzy generalized semi open set (IFGSOS for short) and intuitionistic fuzzy regular generalized αopen set (IFRGαOS for short) if the complement of A is an IFGCS, IFαGCS, IFGSCS and IFRGαCS respectively. 
Definition 2.10: [7] An IFS A in an IFTS (X, τ) is said to be an intuitionistic fuzzy regular weakly generalized closed set (IFRWGCS for short) if cl(int(A)) ⊆ U whenever A ⊆ U, U is IFROS in X. An IFS A is said to be an intuitionistic fuzzy regular weakly generalized open set (IFRWGOS for short) in (X, τ) if the complement of A is an IFRWGCS in X. 
Definition 2.11: [4] Let (X, τ) and (Y, σ) be two intuitionistic fuzzy topological spaces and let f ∶ X→ Y be a function. Then f is said to be an intuitionistic fuzzy continuous if the pre image of each intuitionistic fuzzy open set of Y is an intuitionistic fuzzy open set in X. 
Definition 2.12: [5] Let f be a mapping from an IFTS (X,τ) into an IFTS (Y,σ). Then f is said to be an (i) intuitionistic fuzzy αcontinuous (IFα continuous for short)if f1 (B) ∈ IFαO(X) for every B ∈ σ, (ii) intuitionistic fuzzy pre continuous (IFP continuous for short) if f 1(B) ∈ IFPO(X) for every B ∈ σ. 
Definition 2.13: [6] Let (X, τ) and (Y, σ) be two intuitionistic fuzzy topological spaces and let f ∶ X → Y be a function. Then f is called an intuitionistic fuzzy regular generalized αcontinuous (IFRGα continuous for short) if f 1(A) is an IFRGαCS in (X, τ) for every IFCS A of (Y, σ). Definition 2.14: [8] Let f be a mapping from an IFTS (X,τ) into an IFTS (Y,σ). Then f is called an intuitionistic fuzzy regular weakly generalized continuous (IFRWG continuous for short) if f 1(A) is an IFRWGCS in (X, τ) for every IFCS A of (Y, σ). 
INTUITIONISTIC FUZZY wgrαCLOSED SETS and INTUITIONISTIC FUZZY wgrαOPEN SETS 
In this section we introduced intuitionistic fuzzy wgrαclosed set, intuitionistic fuzzy wgrαopen set and have studied some of its properties. 
Definition 3.1: An IFS A in an IFTS (X,τ) is said to be an intuitionistic fuzzy wgrαclosed set (IFWGRαCS for short) if cl(int(A)) ⊆ U whenever A ⊆ U and U is IFRαOS in X. The complement of the IFWGRαCS is an IFWGRαOS in (X,τ). The family of all IFWGRαCSs of an IFTS (X, τ) is denoted by IFWGRαCS(X). For the sake of simplicity, we shall use the notation A= ⟨x, (μ, μ), (ν, ν)⟩ instead of A= ⟨x,(a/μa, b/μb), (a/νa, b/νb)⟩ in all the examples used in this paper. Similarly we shall use the notation B= ⟨x, (μ, μ), (ν, ν)⟩ instead of B= ⟨x,(u/μu, v/μv), (u/νu, v/νv)⟩ in the following examples. 
Example 3.2: Let X = {a, b} and G = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩. Then τ = {0~, G, 1~} is an IFT on X and the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7)⟩ is an IFWGRαCS in (X, τ). 
Result 3.3: Every IFROS is an IFRαOS. Proof: Let A be an IFROS in X. Therefore int(cl(A)) = A. Since A ⊆ cl(A) = cl(int(cl(A))) implies A ⊆ A ∪ cl(int(cl(A))) = αcl(A). Therefore A ⊆ A ⊆ αcl(A). Hence A is an IFRαOS. Theorem 3.4: Every IFCS in (X, τ) is an IFWGRαCS in (X, τ) but not conversely. Proof: Let A be an IFCS in (X, τ). Let A ⊆ U and U be an IFRαOS in (X, τ). Since A is an intuitionistic fuzzy closed, cl(A) = A and hence cl(A) ⊆ U. But cl(int(A)) ⊆ cl(A) ⊆ U. Therefore cl(int(A)) ⊆ U. Hence A is an IFWGRαCS in (X, τ). Example 3.5: Let X = {a, b} and G = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩. Then τ = {0~, G, 1~} is an IFT on X and the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7)⟩ is an IFWGRαCS but not an IFCS in X. Theorem 3.6: Every IFRCS in (X, τ) is an IFWGRαCS in (X, τ) but not conversely. Proof: Let A be an IFRCS in (X, τ). Let A ⊆ U and U be an IFRαOS in (X, τ). Since A is IFRCS, cl(int(A)) = A ⊆ U. This implies cl(int(A)) ⊆ U. Hence A is an IFWGRαCS in (X,τ). Example 3.7: In Example 3.2., the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7)⟩ is an IFWGRαCS but not an IFRCS in (X, τ). Theorem 3.8: Every IFαCS in (X, τ) is an IFWGRαCS in (X, τ) but not conversely. Proof: Let A be an IFαCS in (X, τ). Let A ⊆ U and U be an IFRαOS in (X, τ). By hypothesis, cl(int(cl(A))) ⊆ A. Therefore cl(int((A)) ⊆ cl(int(cl(A))) ⊆ A ⊆ U. Therefore cl(int((A)) ⊆ U. Hence A is an IFWGRαCS in (X, τ). Example 3.9: In Example 3.2., the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7)⟩ is an IFWGRαCS but not an IFαCS in (X, τ). Theorem 3.10: Every IFPCS in (X, τ) is an IFWGRαCS in (X, τ) but not conversely. Proof: Let A be an IFPCS in (X, τ). Let A ⊆ U and U be an IFRαOS in (X, τ). By definition, cl(int(A)) ⊆ A and A ⊆ U. Therefore cl(int(A) ⊆ U. Hence A is an IFWGRαCS in X. Example 3.11: Let X = {a, b} and G = ⟨x, (0.7, 0.9), (0.3, 0.1)⟩. Then τ = {0~, G, 1~} is an IFT on X and the IFS A = G is an IFWGRαCS but not an IFPCS in (X, τ). Theorem 3.12: Every IFRGαCS in (X, τ) is an IFWGRαCS in (X, τ) but not conversely. Proof: Let A be an IFRGαCS in (X, τ). Let A ⊆ U and U be an IFRαOS in (X, τ). By definition, αcl(A) = A ∪ cl(int(cl(A))) ⊆ U. This implies cl(int(cl(A))) ⊆ U and cl(int(A)) ⊆ cl(int(cl(A))) ⊆ U. Therefore cl(int(A)) ⊆U. Henece A is an IFWGRαCS in (X, τ). Example 3.13: In Example 3.2., the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7) ⟩ is an IFWGRαCS but not an IFRGαCS in (X, τ). 
Theorem 3.14: Every IFWGRαCS in (X, τ) is an IFRWGCS in (X, τ) but not conversely. 
Proof: Let A be an IFWGRαCS in (X, τ). Let A ⊆ U and U be an IFROS in (X, τ). Since every IFROS is an IFRαOS and by hypothesis cl(int(A)) ⊆U. Hence A is an IFRWGCS in (X, τ). 
Example 3.15: Let X = {a, b} and G = ⟨x, (0.2, 0.3), (0.5, 0.6)⟩. Then τ = {0~, G, 1~} is an IFT on X and the IFS A = ⟨x, (0.4, 0.4), (0.5, 0.4)⟩ is an IFRWGCS but not an IFWGRαCS in (X, τ). Proposition 3.16: IFSCS and IFWGRαCS are independent to each other which can be seen from the following example. Example 3.17: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.5, 0.2), (0.5, 0.6)⟩. Then the IFS A = G is an IFSCS but not an IFWGRαCS in X. Example 3.18: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩. Then the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7)⟩ is an IFWGRαCS but not an IFSCS in X. Proposition 3.19: IFGSCS and IFWGRαCS are independent to each other which can be seen from the following example. Example 3.20: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.5, 0.2), (0.5, 0.6)⟩. Then the IFS A = G is an IFGSCS but not an IFWGRαCS in X. Example 3.21: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.7, 0.9), (0.3, 0.1)⟩. Then the IFS A = ⟨x, (0.6, 0.7), (0.4, 0.3)⟩ is an IFWGRαCS but not an IFGSCS in X. Proposition 3.22: IFGCS and IFWGRαCS are independent to each other which can be seen from the following example. Example 3.23: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.5, 0.2), (0.5, 0.6)⟩. Then the IFS A = ⟨x, (0.5, 0.3), (0.5, 0.6)⟩ is an IFGCS but not an IFWGRαCS in X. Example 3.24: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩. Then the IFS A = ⟨x, (0.2, 0.2), (0.8, 0.7)⟩ is an IFWGRαCS but not an IFGCS in X. Proposition 3.25: IFWGCS and IFWGRαCS are independent to each other which can be seen from the following example. Example 3.26: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.5, 0.2), (0.5, 0.6)⟩. Then the IFS A = ⟨x, (0.5, 0.3), (0.5, 0.6)⟩ is an IFWGCS but not an IFWGRαCS in X. Example 3.27: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.8, 0.9), (0.2, 0.1)⟩. Then the IFS A = ⟨x, (0.7, 0.8), (0.3, 0.2)⟩ is an IFWGRαCS but not an IFWGCS in X. Proposition 3.28: IFαGCS and IFWGRαCS are independent to each other which can be seen from the following example. Example 3.29: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.5, 0.2), (0.5, 0.6)⟩. Then the IFS A = ⟨x, (0.5, 0.3), (0.5, 0.6)⟩ is an IFαGCS but not an IFWGRαCS in X. 
Example 3.30: Let X = {a, b} and let τ = {0~, G, 1~} be an IFT on X, where G = ⟨x, (0.8, 0.9), (0.2, 0.1)⟩. Then the IFS A = ⟨x, (0.7, 0.8), (0.3, 0.2)⟩ is an IFWGRαCS but not an IFαGCS in X. The following implications are the relations between intuitionistic fuzzy weakly generalized regular αclosed set and other existing intuitionistic fuzzy closed sets: 
In this diagram by “A B” we mean A implies B but not conversely and “A B” means A and B are independent of each other. 
Remark 3.31: The union of any two IFWGRαCSs in (X, τ) is not an IFWGRαCS in (X, τ) in general as seen from the following example. 
Example 3.32: Let X= {a, b} and let τ= {0~, G, 1~} where G = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩. Then the IFSs A = ⟨x, (0.2, 0.4), (0.8, 0.6)⟩ and B = ⟨x, (0.3, 0.2), (0.7, 0.8)⟩ are IFWGRαCSs in (X, τ) but A ∪ B = ⟨x, (0.3, 0.4), (0.7, 0.6)⟩ is not an IFWGRαCS in (X, τ). Let U = ⟨x, (0.3, 0.4), (0.7, 0.6)⟩ be an IFRαOS in (X, τ). Since A∪B ⊆ U but cl(int(A∪B)) ⊈U. 
Remark 3.33: The intersection of any two IFWGRαCSs in (X, τ) is not an IFWGRαCS in (X, τ) in general as seen from the following example. 
Example 3.34: Let X= {a, b} and let τ = {0~, G, 1~} where G = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩. Then the IFSs A = ⟨x, (0.6, 0.8), (0.4, 0.2)⟩ and B = ⟨x, (0.9, 0.4), (0.1, 0.6)⟩ are IFWGRαCSs in (X, τ) but A∩B =⟨x, (0.6, 0.4), (0.4, 0.6)⟩ is not an IFWGRαCS in (X, τ). Let U = ⟨x, (0.6, 0.4), (0.4, 0.6)⟩ be an IFRαOS in X. Since A∩B ⊆ U but cl(int(A∩B)) ⊈ U. Theorem 3.35: Let A be an IFWGRαCS in (X, τ), then cl(int(A))−A does not contain any nonempty IFRαOS. Proof: Let F be a nonempty IFRαOS such that F ⊆ cl(int(A))−A. Then F ⊆ X−A⇒ A⊆ X−F, X−F is an IFRαOS. Since A is an IFWGRαCS, cl(int(A)) ⊆X−F. Therefore F ⊆ cl(int(A)) ∩ X−cl(int(A)), which implies F = υ, which is a contradiction. Hence cl(int(A)) −A does not contain any nonempty IFRαOS. Theorem 3.36: For an element x ∈ X, then the set X−{x} is an IFWGRαCS or IFRαOS. 
Proof: Suppose X−{x} is not IFRαOS. Then X is the only IFRαOS containing X−{x}⇒ cl(int({X−{x}})) ⊆ X. Therefore X−{x} is an IFWGRαCS. Theorem 3.37: A is an IFWGRαCS of X such that A ⊆ B⊆cl(int(A)), then B is an IFWGRαCS in X. Proof: If A is an IFWGRαCS of X such that A ⊆ B⊆cl(int(A)). Let U be IFRαOS of X such that B ⊆ U, then A ⊆ U. Since A is an IFWGRαCS, cl(int(A)) ⊆U. Now cl(int(B)) ⊆cl(int(cl(int(A)))) = cl(int(A)) ⊆ U. Thus B is an IFWGRαCS in X. Theorem 3.38: If A is an IFWGRαCS and an IFROS, then A is an IFRGCS. Proof: Let A ⊆ U and U be an IFROS. By hypothesis, cl(A) ⊆ U. Therefore A is an IFRGCS. Theorem 3.39: Let A be an IFWGRαCS in (X, τ), then A is an IFRCS iff cl(int(A)) −A is an IFRαOS. Proof: Suppose A is an IFRCS in X. Then cl(int(A)) = A and so cl(int(A))−A = υ, which is an IFRαOS in X. Conversely, Suppose cl(int(A))−A is an IFRαOS in X. Then cl(int(A)) −A = υ. Hence A is an IFRCS in X. 
Theorem 3.40: A subset A of a topological space X is an IFWGRαOS iff F⊆int(cl(A)), whenever F is an IFRαOS and F ⊆ A. 
Proof: Assume A is an IFWGRαOS, Ac is an IFWGRαCS. Let F be an IFRαOS in X contained in A. Fc is an IFRαOS in X containing Ac. Since Ac is an IFWGRαCS, cl(int(Ac) ⊆ Fc . Therefore F ⊆ int(cl(A)). Conversely, let F ⊆int(cl(A)) whenever F ⊆ A and F is an IFRαOS in X. Let G be an IFRαOS containing Ac then Gc ⊆ int(cl(A)). Thus cl(int(Ac)) ⊆G ⊆Ac is an IFWGRαCS ⊆ A is an IFWGRαOS. 
Theorem 3.41: If A ⊆ X is an IFWGRαCS, then cl(int(A)) −A is an IFWGRαOS. 
Proof: Let A be an IFWGRαCS and F be an IFRαOS. F ⊆ cl(int(A)) −A, then int(cl((cl(int(A)) − A))) = υ. Thus F ⊆ int(cl((cl(int(A)) − A))). Therefore cl(int(A)) − A is an IFWGRαOS. 
Theorem 3.42: If int(cl(A)) ⊆B⊆A and A is an IFWGRαOS, then B is an IFWGRαOS. 
Proof: Let int(cl(A)) ⊆B ⊆ A. Thus X−A ⊆ X−B ⊆ cl(int(X−A)). Since X−A is an IFWGRαCS, by theorem 3.37, X−B is an IFWGRαCS. 
INTUITIONISTIC FUZZY wgrαCONTINUOUS MAPPINGS and INTUITIONISTIC FUZZY wgrαIRRESOLUTE MAPPINGS 
Definition 4.1: A mapping f: (X, τ) → (Y, σ) is called an intuitionistic fuzzy wgrαcontinuous (IFWGRα continuous for short) mappings if f 1(V) is an IFWGRαCS in (X, τ) for every IFCS V of (Y, σ). Example 4.2: Let X= {a, b}, Y= {u, v} and G1 = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩, G2 = ⟨y, (0.8, 0.7), (0.2, 0.2)⟩. Then τ = {0~, G1, 1~} and σ = {0~, G2, 1~} are IFTs on X and Y respectively. Define a mapping f: (X, τ) → (Y, σ) by f(a) = u and f(b) = v. Then f is an IFWGRαcontinuous mapping. Definition 4.3: A mapping f: (X, τ) → (Y, σ) is called an intuitionistic fuzzy wgrαirresolute (IFWGRα irresolute for short) mappings if f 1(V) is an IFWGRαCS in (X, τ) for every IFWGRαCS V of (Y, σ). 
Example 4.4: Let X= {a, b}, Y= {u, v} and G1 = ⟨x, (0.3, 0.3), (0.7, 0.7)⟩, G2 = ⟨y, (0.8, 0.7), (0.2, 0.2)⟩. Then τ = {0~, G1, 1~} and σ = {0~, G2, 1~} are IFTs on X and Y respectively. Define a mapping f: (X, τ) → (Y, σ) by f(a) = u and f(b) = v. Then f is an IFWGRα irresolute mapping. 
Theorem 4.5: 
(i) Every IF continuous mappings is an IFWGRα continuous mappings 
(ii) Every IFα continuous mappings is an IFWGRα continuous mappings 
(iii) Every IFP continuous mappings is an IFWGRα continuous mappings 
(iv) Every IFRGα continuous mappings is an IFWGRα continuous mappings 
(v) Every IFWGRα continuous is an IFRWG continuous 
Proof: straight forward. 
Remark 4.6: Converse of the above need not be true. 
Example 4.7: In Example 4.2, f: (X, τ) → (Y, σ) is an IFWGRα continuous mapping but not an IF continuous mapping. Since G2 = ⟨y, (0.8, 0.7), (0.2, 0.2)⟩ is an IFOS in Y but f 1(G2) = ⟨x, (0.8, 0.7), (0.2, 0.2)⟩ is not an IFOS in X. 
Example 4.8: In Example 4.2, f: (X, τ) → (Y, σ) is an IFWGRα continuous mapping but not an IFα continuous mapping. Since G2 = ⟨y, (0.8, 0.7), (0.2, 0.2)⟩ is an IFOS in Y but f 1(G2) = ⟨x, (0.8, 0.7), (0.2, 0.2)⟩ is not an IFαOS in X. 
Example 4.9: Let X = {a, b}, Y = {u, v} and G1 = ⟨x, (0.7, 0.9), (0.3, 0.1)⟩, G2 = ⟨y, (0.3, 0.1), (0.7, 0.9)⟩. Then τ = {0~, G1, 1~} and σ = {0~, G2, 1~} are IFTs on X and Y respectively. Define a mapping f: (X, τ) → (Y, σ) by f(a) = u and f(b) = v. Then f is an IFWGRα continuous mapping but not an IFP continuous mapping. Example 4.10: In Example 4.2, f: (X, τ) → (Y, σ) is an IFWGRα continuous mapping but not an IFRGα continuous mapping. Since G2 = ⟨y, (0.8, 0.7), (0.2, 0.2)⟩ is an IFOS in Y but f 1(G2) = ⟨x, (0.8, 0.7), (0.2, 0.2)⟩ is not an IFRGαOS in X. 
Example 4.11: Let X = {a, b}, Y = {u, v} and G1 = ⟨x, (0.2, 0.3), (0.5, 0.6)⟩, G2 = ⟨y, (0.5, 0.4), (0.4, 0.4)⟩. Then τ = {0~, G1, 1~} and σ = {0~, G2, 1~} are IFTs on X and Y respectively. Define a mapping f: (X, τ) → (Y, σ) by f(a) = u and f(b) = v. Then f is an IFRWG continuous mapping but not an IFWGRα continuous mapping. 
Theorem 4.12: Let f: (X, τ) → (Y, σ) be a mapping where f 1(V) is an IFRCS in X for every IFCS in Y. Then f is an IFWGRα continuous mapping but not conversely. 
Proof: Let A be an IFCS in Y. Then f 1(V) is an IFRCS in X. Since every IFRCS is an IFWGRαCS, f 1(V) is an IFWGRαCS in X. Hence f is an IFWGRα continuous mapping. 
Example 4.13: In Example 4.2, f: (X, τ) → (Y, σ) is an IFWGRα continuous mapping but but not a mapping defined in theorem 4.12. 
Theorem 4.14: Let f: (X, τ) → (Y, σ) and g: (Y, σ) → (Z, η) be any two maps. Then 
(i) g ∘ f is IFWGRα continuous, if g is IF continuous and f is IFWGRα continuous 
(ii) g ∘ f is IFWGRα irresolute, if g is IFWGRα irresolute and f is IFWGRα irresolute 
(iii) g ∘ f is IFWGRα continuous, if g is IFWGRα continuous and f is IFWGRα irresolute 
Proof: 
(i) Let V be any IFCS in (Z, η). Then g1(V) is an IFCS in (Y, σ), since g is IF continuous. By hypothesis, f1(g1(V)) is an IFWGRαCS in (X, τ). Hence g ∘ f is IFWGRα continuous. (ii) Let V be an IFWGRαCS in (Z, η). Since g is IFWGRα irresolute, g1(V) is IFWGRαCS in (Y, σ). As f is IFWGRα irresolute, f1(g1(V)) = (g ∘ f)1(V) is an IFWGRαCS in (X, τ). Hence g ∘ f is IFWGRα irresolute. (iii) Let V be an IFCS in (Z, η). Since g is IFWGRα continuous,g1(V) is an IFWGRαCS in (Y, σ). As f is IFWGRα irresolute, f1(g1(V)) = (g ∘ f)1(V) is an IFWGRαCS in (X, τ). Hence g ∘f is IFWGRα continuous. 
APPLICATIONS OF INTUITIONISTIC FUZZY wgrαCLOSED SETS 
In this section we have provide some applications of intuitionistic fuzzy wgrαclosed sets in intuitionistic fuzzy topological spaces. 
Definition 5.1: A space (X,τ) is called IFwgrαT1\2 space if every IFWGRαCS is an IFαCS. 
Definition 5.2: A space (X,τ) is called IFwgrT1\2 space if every IFWGRαCS is an IFCS. 
Theorem 5.3: For an IFTS (X, τ) the following conditions are equivalent 
(i) X is IFwgrαT1\2 space. 
(ii) Every singleton of X is either IFRαCS (or) IFαOS. 
Proof: (i)⇔(ii) Let x ∈ X and assume that {x} is not IFRαCS. Then clearly X−{x} is not IFRαOS and X{x} is trivially IFWGRαCS. By (i) it is IFαCM and thus {x} is IFαOS. (ii) ⇔ (i) let A ⊂ X be an IFWGRαCS. Let x ∈ cl(int(A)). To show x ∈ A. Case (i) the set {x} is an IFRαCS. Then if x ∉ A, then A ⊆ X{x}. Since X is IFWGRαCS and X{x}is an IFRαOS, cl(int(A)) ⊆ X{x}and hence x ∉ cl(int(A)). This is a contradiction. Therefore, x ∈ A. Case (ii) the set {x} is an IFαOS. Since x ∈ cl(int(A)), then {x} ∩ A ≠ υ implies x ∈ A. In both the cases x ∈ A. This shows that A is an IFαCS. 
Theorem 5.4: Let (X, τ) be an IFTS and (Y, σ) be an IFwgrT1\2 space and f: (X, τ) → (Y, σ) be a map. Then the following are equivalent. 
(i) f is IFWGRα irresolute. 
(ii) f is IFWGRα continuous. 
Proof: (i) ⇒ (ii) Let U be an IFCS in (Y, σ). Since f is an IFWGRα irresolute, f1(U) is an IFWGRαCS in (X, τ). Thus f is IFWGRα continuous. (ii) ⇒ (i) Let F be an IFWGRαCS in (Y, σ). Since Y is an IFwgrT1\2 space, F is an IFCS in Y. By hypothesis f1(F) is an IFWGRαCS in X. Therefore f is an IFWGRα irresolute. 
Theorem 5.5: 
(i) IFαO(X, τ) ⊂ IFWGRαO(X, τ). 
(ii) A space is an IFwgrαT1\2 space if and only if IFαO(X, τ) = IFWGRαO(X, τ). 
Proof: (i) Let A be an IFαOS. Therefore X−A is an IFαCS. Every IFαCS is an IFWGRαCS. Therefore X−A is an IFWGRαCS, which implies A is an IFWGRαOS. (ii) Let X be an IFwgrαT1\2 space. Let A ∈ IFWGRαO(X, τ), X – A is an IFWGRαCS implies X−A is IFαCS. Hence A ∈ IFαO(X, τ). Therefore IFWGRαO(X, τ) ⊂ IFαO(X, τ) and IFαO(X, τ) ⊆ IFWGRαO(X, τ). Which implies IFαO(X, τ) = IFWGRαO(X, τ). Conversely, let IFαO(X, τ) = IFWGRαO(X, τ). A is IFWGRαCS implies X−A is an IFWGRαOS. By assumption X−A is an IFαOS and hence A is IFαCS. 
Theorem 5.6: Let (Y, σ) be an IFwgrT1\2 space, f: (X, τ) → (Y, σ) and g: (Y, σ) → (Z, η) be two IFWGRα continuous functions, then g ∘ f: (X,τ) → (Z,η) is also an IFWGRα continuous. 
Proof: Let V be any IFCS in (Z, η). Since g1(V) is IFWGRαCS in (Y, σ). IFWGRα continuity of f implies that f1(g1(V)) = (g ∘ f)1(V) is an IFWGRαCS. Hence (g ∘ f) is an IFWGRα continuous. 
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